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    Open debug window from code

    The runcommand acCmdVisualBasicEditor only works in XP and higher. I'm stuck with access2000. But the runcommand acCmdDebugWindow works perfect.
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    Open debug window from code

    Thank you Peter
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    Open debug window from code

    Hi, Is it possible to open the debug window from code. In my startup options, i blocked the ctrl + g to open the debug window. Now i want a command button with code to be able to open the debug window after i type in the correct password. What code do i have to use? Frank
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    MD5 Hashing

    Thanks, I was looking for something like that. Works like a charm. Frank
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    Import multiple Excel Spreadsheets into one table

    I'm one of those other people:) Thanks Frank
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    autonumber field in txt format

    Is your field txtCIATAsiaNo numeric? If so, change the format of txtCIATAsiaNo to "00000" It's even better to change the format of the field in your table. If you create a report or form, then the format will be taken over. Frank
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    Stopping Duplicate Value Entries

    stLinkCriteria = "[Date_Required] =" & chr(35) & format(D,"mm/dd/yy") & chr(35)
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    autonumber field in txt format

    Try this: Me!txtCIATAsiaNo.DefaultValue = format(Nz(DMax("[CIATinAsiaCode]", "Assets"), 0) + 1,"00000") Frank
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    Get control name

    Screen.ActiveControl.Name
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    stLinkCriteria Date & Text

    Try this: stLinkCriteria3 = "[StartDate] = #" & testdate & "# And [Unit] = " & Chr(34) & Me!CboUnit & Chr(34) Frank
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    Help For Hiding Password Typing Entry Xxxxx

    You cannot format an inputbox. What you can do, is create a new form with just one textbox. You then must do what jkl0 says: set the Input mask to "Password" The result from the textbox you put in a variable. Frank
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    Problem with recordset (fieldname = variable)

    Thanks ejstefl, That was exactly what i was looking for. I didn't use the loop, but make the folowing changes rslogin.AddNew rslogin.Fields(User) = fOSUserName() rslogin.Fields(Computer) = fOSMachineName() rslogin.Fields(InOut) = remark rslogin.update I couldn't use "type", because it's a...
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    Problem with recordset (fieldname = variable)

    Thanks for trying. Anybody else got an idea? Frank
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    Problem with recordset (fieldname = variable)

    The msgbox gives me the value of the variable (as it should) and not the name of the variable I only want to know how to adress a recordsetfield, if the fieldname is in a variable. Frank
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    Problem with recordset (fieldname = variable)

    I think that the incoming arguments are already seen als variables. The problem is that access doesn't look at those variables as variables, because they are behind the "!". I had the same problem with code for a form: myform.updatefield had to be changed to myform.Controls(updatefield) I'm...
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    Problem with recordset (fieldname = variable)

    Hello, I'm trying to create a general module, that i can use in different databases. Sub FLogin(tablename, user, computer, InOut, type) Dim rslogin As DAO.Recordset Set rslogin = CurrentDb.OpenRecordset(tablename, dbOpenDynaset) rslogin.AddNew rslogin!user = fOSUserName() rslogin!computer =...
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    Filter Query By Date

    if it really is in a query, create an extra field: selectdate: format (fieldname,"mm/dd") then in criteria you put format(date,"mm/dd")
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    If function

    dim rs as recordset dim testsql as string testsql = "SELECT Product FROM ...." set rs = currentdb.openrecordset(testsql) if rs.eof then ... else ... end if
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    Combo box col 3

    have you tried to set the value of controlsource of txtJobDesc to '= JobName.Column(2)' This should work without VBA
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    Combo box col 3

    "Column" starts counting at 0 So if you want the value from the third column, you need JobName.Column(2) If you just want to make it visible, why don't you set the controlsource of txtJobDesc = JobName.Column(2)
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