group query listbox - amend each record represented by grouped listbox item(s)

[NBRJ]

I have a listbox on a form that is based off a grouped query. For example:

Listbox: lstRequestedSoftwareAmalgamated
Query: qRequestedSoftwareAmalgamated, with the following fields grouped:

• Title (group by)
• Version (group by)
• ConfigInfo (group by)
• [other grouped fields...]
• Locations (count of IDRequestDetail)

I then have some text boxes on the (unbound) form. When I select one or more items from the listbox, lstRequestedSoftwareAmalgamated, and then click a button (cmdDecision) I want to send the contents of these boxes to fields for each record in the group represented by the selected item(s) in the listbox.

How can I do this? When each selected listbox items represents just one record I can do that, but how do I get it to cycle though that group of records a selected line in the listbox represents.

So 1 list item could be:
Title: Illustrator
Version: 2016
ConfigInfo: [user config text here]
Locations: 20
And that would represent 20 records grouped.

So when they select that listbox item, I want the fields on the form to add data to field(s) for each 20 records.

I need this to be a listbox, because a user will be selecting more than one (grouped) item at a time to insert field data into.

Thanks for any pointers

 

[pbaldy]

Not clear on the goal, but either running an append query or opening a recordset, either way using SQL that used the fields being grouped on in the criteria. Using your example and pseudo-SQL:

SELECT...
FROM...
WHERE Title = Illustrator AND Version = 2016 AND ConfigInfo = [user config text here]

Obviously you'd have to build the SQL and concatenate the values from the listbox into the string.

 

[NBRJ]

ah-ha, I was just thinking about trying that, I'm glad I was on the right lines. I basically take the column data in the selected grouped list item, find the records that match that content and then append... I can pull in the FIDs of the fields and keep them hidden from the list and do it via that, so that's relatively easy, I'd think. Thank you!

 

[pbaldy]

No problem, post back if you get stuck.