Here is a question I asked the Chat GPT. It did not have a solution, just a few possible causes.
User
Why does this hyperlink not work with this type of address? It works great with most hyperlinks but not this one.
Non functional hyperlink, but works when pasted into browser.
Hopefully this will be one of those time where a human will outperform an AI.
Thanks all.
User
Why does this hyperlink not work with this type of address? It works great with most hyperlinks but not this one.
Non functional hyperlink, but works when pasted into browser.
Code:
Call GoHyperlink(Me.txtAttachment)
'Purpose: Avoid warning and error messages when opening files with FollowHyperlink
'Author: Allen Browne (allen@allenbrowne.com)
'Release: 28 January 2008
'Usage: To open MyFile.doc in Word, use:
' GoHyperlink "MyFile.doc"
' instead of:
' FollowHyperlink "MyFile.doc"
'Rationale:
'FollowHyperlink has several problems:
' a) It errors if a file name contains characters such as #, %, or &.
' b) It can give unwanted warnings, e.g. on a fileame with "file:///" prefix.
' c) It yields errors if the link did not open.
'This replacement:
' a) escapes the problem characters
' b) prepends the prefix
' c) returns True if the link opened (with an optional error message if you care.)
'Limitations:
' - If a file name contains two # characters, it is treated as a hyperlink.
' - If a file name contains % followed by 2 hex digits, it assumes it is pre-escaped.
' - File name must include path.
'Documentation: http://allenbrowne.com/func-GoHyperlink.html
Public Function GoHyperlink(FullFilenameOrLink As Variant) As Boolean
On Error GoTo Err_Handler
'Purpose: Replacement for FollowHyperlink.
'Return: True if the hyperlink opened.
'Argument: varIn = the link to open
Dim strLink As String
Dim strErrMsg As String
'Skip error, null, or zero-length string.
If Not IsError(FullFilenameOrLink) Then
If FullFilenameOrLink <> vbNullString Then
strLink = PrepHyperlink(FullFilenameOrLink, strErrMsg)
If strLink <> vbNullString Then
FollowHyperlink strLink
'Return True if we got here without error.
GoHyperlink = True
End If
'Display any error message from preparing the link.
If strErrMsg <> vbNullString Then
MsgBox strErrMsg, vbExclamation, "PrepHyperlink()"
End If
End If
End If
Exit_Handler:
Exit Function
Err_Handler:
MsgBox "Error " & Err.Number & ": " & Err.Description, vbExclamation, "GoHyperlink()"
Resume Exit_Handler
End FunctionHopefully this will be one of those time where a human will outperform an AI.
Thanks all.
Last edited:
